
∵∠1=∠BAC∠1=∠BAD+∠ABE∠BAC=∠BAD+∠CAF∴∠ABE=∠CAF同理∠BAD=∠ACF∵AB=AC∴⊿ABE≌⊿ACF(ASA)∴S⊿ABE=S⊿ACF∴△ABE与△CDF面积之和=S⊿ACF+S⊿CDF=S⊿ACD=2/3S⊿ABC ﹙∵CD=2BD ∴CD=2/3BC﹚=2/3×9=6

∵∠1=∠BAC∠1=∠BAD+∠ABE∠BAC=∠BAD+∠CAF∴∠ABE=∠CAF同理∠BAD=∠ACF∵AB=AC∴⊿ABE≌⊿ACF(ASA)∴S⊿ABE=S⊿ACF∴△ABE与△CDF面积之和=S⊿ACF+S⊿CDF=S⊿ACD=2/3S⊿ABC ﹙∵CD=2BD ∴CD=2/3BC﹚=2/3×9=6